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Homogeneity of Variance of The Groups and Normality
Assumptions of Homogeneity of Variance of The Groups and Normality
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Order Number |
7823789876665 |
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Type of Project |
ESSAY |
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Writer Level |
PHD VERIFIED |
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Format |
APA |
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Academic Sources |
10 |
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Page Count |
3-12 PAGES |
Instructions/Descriptions
Assumptions of Homogeneity of Variance of The Groups and Normality
Step-by-Step Guide Assignment Problem 3.3
2-Way ANOVA
Problem 3. Discuss whether the assumptions of homogeneity of variance of the groups and normality of the data on Exercise are met. Be sure to include output to support your decision on whether the assumptions have been met. (Continue with the analyses even if assumptions are not met.)
Review:
Homogeneity of variance means that the variance about the means is equal among the independent variables.
Normality means that the data for each level of the independent variables are normally distributed.
Step 1. Open the SPSS Practice data set if you have closed it.
Step 2. Go to Analyze(Descriptive Statistics(Explore
Step 3. In Explore window, place Steps per month [EXERCISE] in the Dependent List. Place Education level [EDUC] and Sex [SEX] in the Factor List. Click on Plots…
Step 4. Select None in Boxplots, check Normality plots with tests, and select Power estimation in Spread vs Level with Levene’s Test. Click Continue.
Step 5. In the Explore window, make sure Both is selected in Display then click OK.
Step 6. Locate and examine the Test of Homogeneity of Variance for SEX and EDUC in the Output:
SEX:
| Test of Homogeneity of Variance | |||||
| Levene Statistic | df1 | df2 | Sig. | ||
| Steps per month | Based on Mean | 5.328 | 1 | 98 | .023 |
| Based on Median | 3.932 | 1 | 98 | .050 | |
| Based on Median and with adjusted df | 3.932 | 1 | 87.549 | .051 | |
| Based on trimmed mean | 4.938 | 1 | 98 | .029 |
EDUC
| Test of Homogeneity of Variance | |||||
| Levene Statistic | df1 | df2 | Sig. | ||
| Steps per month | Based on Mean | 2.072 | 2 | 97 | .131 |
| Based on Median | 1.748 | 2 | 97 | .180 | |
| Based on Median and with adjusted df | 1.748 | 2 | 89.800 | .180 | |
| Based on trimmed mean | 1.978 | 2 | 97 | .144 |
Step 7. Locate and examine the Tests of Normality tables for both Sex and Education level:
SEX
| Tests of Normality | |||||||
| Sex | Kolmogorov-Smirnova | Shapiro-Wilk | |||||
| Statistic | df | Sig. | Statistic | df | Sig. | ||
| Steps per month | Male | .130 | 49 | .038 | .915 | 49 | .002 |
| Female | .139 | 51 | .015 | .929 | 51 | .005 | |
| a. Lilliefors Significance Correction |
EDUC
| Tests of Normality | |||||||
| Education level | Kolmogorov-Smirnova | Shapiro-Wilk | |||||
| Statistic | df | Sig. | Statistic | df | Sig. | ||
| Steps per month | No or some high school | .181 | 16 | .170 | .895 | 16 | .066 |
| High school diploma | .222 | 31 | .000 | .872 | 31 | .002 | |
| College Degree | .115 | 53 | .076 | .932 | 53 | .005 | |
| a. Lilliefors Significance Correction |
Discussion:
Your discussion must cover issues such as
- Meaning of the test for homogeneity
- Which variables meet the assumptions for the test
- Meaning of the test for normality
- Which variables are normally distributed and why
Assumptions of Homogeneity of Variance of The Groups and Normality
